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551050242130373 is a prime number
BaseRepresentation
bin111110101001011010110000…
…1111011111000000111000101
32200021002212222211121000002212
41331102311201323320013011
51034211401343441132443
65231552553024513205
7224033031462405206
oct17522654173700705
92607085884530085
10551050242130373
1114a644105917a47
125197928b17b805
131a862a7933a90b
149a10d8ca295ad
1543a9134a46618
hex1f52d61ef81c5

551050242130373 has 2 divisors, whose sum is σ = 551050242130374. Its totient is φ = 551050242130372.

The previous prime is 551050242130291. The next prime is 551050242130379. The reversal of 551050242130373 is 373031242050155.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 547030445697124 + 4019796433249 = 23388682^2 + 2004943^2 .

It is a cyclic number.

It is not a de Polignac number, because 551050242130373 - 222 = 551050237936069 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 551050242130373.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (551050242130379) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275525121065186 + 275525121065187.

It is an arithmetic number, because the mean of its divisors is an integer number (275525121065187).

Almost surely, 2551050242130373 is an apocalyptic number.

It is an amenable number.

551050242130373 is a deficient number, since it is larger than the sum of its proper divisors (1).

551050242130373 is an equidigital number, since it uses as much as digits as its factorization.

551050242130373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 378000, while the sum is 41.

The spelling of 551050242130373 in words is "five hundred fifty-one trillion, fifty billion, two hundred forty-two million, one hundred thirty thousand, three hundred seventy-three".