Search a number
-
+
55110010001141 is a prime number
BaseRepresentation
bin11001000011111010011001…
…00100011101011011110101
321020010110120100111110220202
430201331030210131123311
524210410300030014031
6313113104502010245
714415365264646464
oct1441751444353365
9236113510443822
1055110010001141
1116618029a26767
126220832a16985
132499b0c0a6374
14d874a56189db
156588102a22cb
hex321f4c91d6f5

55110010001141 has 2 divisors, whose sum is σ = 55110010001142. Its totient is φ = 55110010001140.

The previous prime is 55110010001107. The next prime is 55110010001159. The reversal of 55110010001141 is 14110001001155.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31048532438641 + 24061477562500 = 5572121^2 + 4905250^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55110010001141 is a prime.

It is a super-2 number, since 2×551100100011412 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55110010001171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27555005000570 + 27555005000571.

It is an arithmetic number, because the mean of its divisors is an integer number (27555005000571).

Almost surely, 255110010001141 is an apocalyptic number.

It is an amenable number.

55110010001141 is a deficient number, since it is larger than the sum of its proper divisors (1).

55110010001141 is an equidigital number, since it uses as much as digits as its factorization.

55110010001141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 100, while the sum is 20.

Adding to 55110010001141 its reverse (14110001001155), we get a palindrome (69220011002296).

The spelling of 55110010001141 in words is "fifty-five trillion, one hundred ten billion, ten million, one thousand, one hundred forty-one".