Base | Representation |
---|---|
bin | 11001000011111010011101… |
… | …11101010100101100011101 |
3 | 21020010110200010220100200111 |
4 | 30201331032331110230131 |
5 | 24210410340304321443 |
6 | 313113112452530021 |
7 | 14415366262365241 |
oct | 1441751675245435 |
9 | 236113603810614 |
10 | 55110050073373 |
11 | 1661804a606609 |
12 | 6220844320911 |
13 | 2499b17496a49 |
14 | d874aaa8a421 |
15 | 658813a6a69d |
hex | 321f4ef54b1d |
55110050073373 has 2 divisors, whose sum is σ = 55110050073374. Its totient is φ = 55110050073372.
The previous prime is 55110050073359. The next prime is 55110050073401. The reversal of 55110050073373 is 37337005001155.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 51326721647289 + 3783328426084 = 7164267^2 + 1945078^2 .
It is a cyclic number.
It is not a de Polignac number, because 55110050073373 - 217 = 55110049942301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55110050070373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27555025036686 + 27555025036687.
It is an arithmetic number, because the mean of its divisors is an integer number (27555025036687).
Almost surely, 255110050073373 is an apocalyptic number.
It is an amenable number.
55110050073373 is a deficient number, since it is larger than the sum of its proper divisors (1).
55110050073373 is an equidigital number, since it uses as much as digits as its factorization.
55110050073373 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 165375, while the sum is 40.
The spelling of 55110050073373 in words is "fifty-five trillion, one hundred ten billion, fifty million, seventy-three thousand, three hundred seventy-three".
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