Base | Representation |
---|---|
bin | 10000000010100000010… |
… | …01111101001100011001 |
3 | 1221200111011000012202120 |
4 | 20001100021331030121 |
5 | 33012123223213423 |
6 | 1101101102251453 |
7 | 54546533550606 |
oct | 10012011751431 |
9 | 1850434005676 |
10 | 551100601113 |
11 | 1a27a1a16447 |
12 | 8a982586b89 |
13 | 3cc78c1bc5a |
14 | 1c95dbab6ad |
15 | e506e2bee3 |
hex | 805027d319 |
551100601113 has 4 divisors (see below), whose sum is σ = 734800801488. Its totient is φ = 367400400740.
The previous prime is 551100601111. The next prime is 551100601159. The reversal of 551100601113 is 311106001155.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 551100601113 - 21 = 551100601111 is a prime.
It is not an unprimeable number, because it can be changed into a prime (551100601111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91850100183 + ... + 91850100188.
It is an arithmetic number, because the mean of its divisors is an integer number (183700200372).
Almost surely, 2551100601113 is an apocalyptic number.
It is an amenable number.
551100601113 is a deficient number, since it is larger than the sum of its proper divisors (183700200375).
551100601113 is a wasteful number, since it uses less digits than its factorization.
551100601113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 183700200374.
The product of its (nonzero) digits is 450, while the sum is 24.
Adding to 551100601113 its reverse (311106001155), we get a palindrome (862206602268).
The spelling of 551100601113 in words is "five hundred fifty-one billion, one hundred million, six hundred one thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •