Base | Representation |
---|---|
bin | 10000000010100000010… |
… | …11111001100101001001 |
3 | 1221200111011222002122111 |
4 | 20001100023321211021 |
5 | 33012123341014401 |
6 | 1101101121222321 |
7 | 54546541102156 |
oct | 10012013714511 |
9 | 1850434862574 |
10 | 551101110601 |
11 | 1a27a2234208 |
12 | 8a9827919a1 |
13 | 3cc79069b22 |
14 | 1c95dca122d |
15 | e506ecce51 |
hex | 80502f9949 |
551101110601 has 4 divisors (see below), whose sum is σ = 551472724432. Its totient is φ = 550729496772.
The previous prime is 551101110421. The next prime is 551101110629. The reversal of 551101110601 is 106011101155.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 106011101155 = 5 ⋅21202220231.
It is a cyclic number.
It is not a de Polignac number, because 551101110601 - 221 = 551099013449 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (551101110631) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 185804691 + ... + 185807656.
It is an arithmetic number, because the mean of its divisors is an integer number (137868181108).
Almost surely, 2551101110601 is an apocalyptic number.
It is an amenable number.
551101110601 is a deficient number, since it is larger than the sum of its proper divisors (371613831).
551101110601 is a wasteful number, since it uses less digits than its factorization.
551101110601 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 371613830.
The product of its (nonzero) digits is 150, while the sum is 22.
Adding to 551101110601 its reverse (106011101155), we get a palindrome (657112211756).
The spelling of 551101110601 in words is "five hundred fifty-one billion, one hundred one million, one hundred ten thousand, six hundred one".
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