Base | Representation |
---|---|
bin | 10000000010100000101… |
… | …11000000000000111101 |
3 | 1221200111101102221100001 |
4 | 20001100113000000331 |
5 | 33012130112124131 |
6 | 1101101303434301 |
7 | 54546604612024 |
oct | 10012027000075 |
9 | 1850441387301 |
10 | 551104020541 |
11 | 1a27a3941518 |
12 | 8a983755991 |
13 | 3cc79848499 |
14 | 1c96041b8bb |
15 | e5073a5261 |
hex | 80505c003d |
551104020541 has 2 divisors, whose sum is σ = 551104020542. Its totient is φ = 551104020540.
The previous prime is 551104020521. The next prime is 551104020629. The reversal of 551104020541 is 145020401155.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 358356679641 + 192747340900 = 598629^2 + 439030^2 .
It is a cyclic number.
It is not a de Polignac number, because 551104020541 - 27 = 551104020413 is a prime.
It is a super-3 number, since 3×5511040205413 (a number of 36 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (551104020521) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275552010270 + 275552010271.
It is an arithmetic number, because the mean of its divisors is an integer number (275552010271).
Almost surely, 2551104020541 is an apocalyptic number.
It is an amenable number.
551104020541 is a deficient number, since it is larger than the sum of its proper divisors (1).
551104020541 is an equidigital number, since it uses as much as digits as its factorization.
551104020541 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4000, while the sum is 28.
Adding to 551104020541 its reverse (145020401155), we get a palindrome (696124421696).
The spelling of 551104020541 in words is "five hundred fifty-one billion, one hundred four million, twenty thousand, five hundred forty-one".
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