Base | Representation |
---|---|
bin | 11001000011111011001010… |
… | …11001110101101000011111 |
3 | 21020010111122101111021200111 |
4 | 30201331211121311220133 |
5 | 24210412123210201241 |
6 | 313113214104110451 |
7 | 14415411514250605 |
oct | 1441754531655037 |
9 | 236114571437614 |
10 | 55110426647071 |
11 | 16618223130a44 |
12 | 622092a465427 |
13 | 2499b774c5513 |
14 | d87504ab3875 |
15 | 658836b52c81 |
hex | 321f65675a1f |
55110426647071 has 4 divisors (see below), whose sum is σ = 55136215337392. Its totient is φ = 55084637956752.
The previous prime is 55110426646969. The next prime is 55110426647113. The reversal of 55110426647071 is 17074662401155.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55110426647071 - 29 = 55110426646559 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55110426641071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12894341955 + ... + 12894346228.
It is an arithmetic number, because the mean of its divisors is an integer number (13784053834348).
Almost surely, 255110426647071 is an apocalyptic number.
55110426647071 is a deficient number, since it is larger than the sum of its proper divisors (25788690321).
55110426647071 is a wasteful number, since it uses less digits than its factorization.
55110426647071 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25788690320.
The product of its (nonzero) digits is 1411200, while the sum is 49.
The spelling of 55110426647071 in words is "fifty-five trillion, one hundred ten billion, four hundred twenty-six million, six hundred forty-seven thousand, seventy-one".
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