Base | Representation |
---|---|
bin | 110011010100110111… |
… | …111111001110000101 |
3 | 12021020210011121221001 |
4 | 303110313333032011 |
5 | 1400331412213323 |
6 | 41152341053301 |
7 | 3660463142305 |
oct | 632467771605 |
9 | 167223147831 |
10 | 55111054213 |
11 | 214108317a6 |
12 | a8206b7231 |
13 | 5273912767 |
14 | 294b45d605 |
15 | 16784363ad |
hex | cd4dff385 |
55111054213 has 2 divisors, whose sum is σ = 55111054214. Its totient is φ = 55111054212.
The previous prime is 55111054157. The next prime is 55111054231. The reversal of 55111054213 is 31245011155.
Together with next prime (55111054231) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 53711770564 + 1399283649 = 231758^2 + 37407^2 .
It is a cyclic number.
It is not a de Polignac number, because 55111054213 - 233 = 46521119621 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55111054613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27555527106 + 27555527107.
It is an arithmetic number, because the mean of its divisors is an integer number (27555527107).
Almost surely, 255111054213 is an apocalyptic number.
It is an amenable number.
55111054213 is a deficient number, since it is larger than the sum of its proper divisors (1).
55111054213 is an equidigital number, since it uses as much as digits as its factorization.
55111054213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3000, while the sum is 28.
Adding to 55111054213 its reverse (31245011155), we get a palindrome (86356065368).
The spelling of 55111054213 in words is "fifty-five billion, one hundred eleven million, fifty-four thousand, two hundred thirteen".
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