Base | Representation |
---|---|
bin | 101000000110010011111… |
… | …0100000110101100111010 |
3 | 201111212010210122200112110 |
4 | 1100030213310012230322 |
5 | 1210243223404324010 |
6 | 15415434111153150 |
7 | 1106110316450124 |
oct | 120144764065472 |
9 | 21455123580473 |
10 | 5511111011130 |
11 | 183528154508a |
12 | 75010bb157b6 |
13 | 30c90713702a |
14 | 150a4c4d6214 |
15 | 98553a21120 |
hex | 50327d06b3a |
5511111011130 has 32 divisors (see below), whose sum is σ = 13922806766400. Its totient is φ = 1392280676352.
The previous prime is 5511111011123. The next prime is 5511111011191. The reversal of 5511111011130 is 311101111155.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 5511111011097 and 5511111011106.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4834307335 + ... + 4834308474.
It is an arithmetic number, because the mean of its divisors is an integer number (435087711450).
Almost surely, 25511111011130 is an apocalyptic number.
5511111011130 is an abundant number, since it is smaller than the sum of its proper divisors (8411695755270).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5511111011130 is a wasteful number, since it uses less digits than its factorization.
5511111011130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9668615838.
The product of its (nonzero) digits is 75, while the sum is 21.
Adding to 5511111011130 its reverse (311101111155), we get a palindrome (5822212122285).
The spelling of 5511111011130 in words is "five trillion, five hundred eleven billion, one hundred eleven million, eleven thousand, one hundred thirty".
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