Base | Representation |
---|---|
bin | 11001000011111100101001… |
… | …11010001010101010111001 |
3 | 21020010120200221012021112120 |
4 | 30201332110322022222321 |
5 | 24210420241223313001 |
6 | 313113425134431453 |
7 | 14415440332545330 |
oct | 1441762472125271 |
9 | 236116627167476 |
10 | 55111223651001 |
11 | 166185a2005881 |
12 | 6220b11362589 |
13 | 2499c7366978b |
14 | d8757c89cd17 |
15 | 658881ad7236 |
hex | 321f94e8aab9 |
55111223651001 has 32 divisors (see below), whose sum is σ = 89226627275520. Its totient is φ = 29639649639168.
The previous prime is 55111223650993. The next prime is 55111223651039. The reversal of 55111223651001 is 10015632211155.
It is a happy number.
It is not a de Polignac number, because 55111223651001 - 23 = 55111223650993 is a prime.
It is not an unprimeable number, because it can be changed into a prime (55111223661001) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 266978446 + ... + 267184791.
It is an arithmetic number, because the mean of its divisors is an integer number (2788332102360).
Almost surely, 255111223651001 is an apocalyptic number.
55111223651001 is a gapful number since it is divisible by the number (51) formed by its first and last digit.
It is an amenable number.
55111223651001 is a deficient number, since it is larger than the sum of its proper divisors (34115403624519).
55111223651001 is an equidigital number, since it uses as much as digits as its factorization.
55111223651001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 534163298 (or 534163264 counting only the distinct ones).
The product of its (nonzero) digits is 9000, while the sum is 33.
Adding to 55111223651001 its reverse (10015632211155), we get a palindrome (65126855862156).
The spelling of 55111223651001 in words is "fifty-five trillion, one hundred eleven billion, two hundred twenty-three million, six hundred fifty-one thousand, one".
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