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55111263124543 is a prime number
BaseRepresentation
bin11001000011111100101110…
…10000101111110000111111
321020010120210200110202001121
430201332113100233300333
524210420331324441133
6313113433104451411
714415441322221463
oct1441762720576077
9236116720422047
1055111263124543
111661861231693a
126220b22619b67
132499c7b8aa7c2
14d87583c164a3
156588852d302d
hex321f9742fc3f

55111263124543 has 2 divisors, whose sum is σ = 55111263124544. Its totient is φ = 55111263124542.

The previous prime is 55111263124531. The next prime is 55111263124553. The reversal of 55111263124543 is 34542136211155.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 55111263124543 - 229 = 55110726253631 is a prime.

It is a super-2 number, since 2×551112631245432 (a number of 28 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 55111263124543.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55111263124553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27555631562271 + 27555631562272.

It is an arithmetic number, because the mean of its divisors is an integer number (27555631562272).

Almost surely, 255111263124543 is an apocalyptic number.

55111263124543 is a deficient number, since it is larger than the sum of its proper divisors (1).

55111263124543 is an equidigital number, since it uses as much as digits as its factorization.

55111263124543 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 432000, while the sum is 43.

Adding to 55111263124543 its reverse (34542136211155), we get a palindrome (89653399335698).

The spelling of 55111263124543 in words is "fifty-five trillion, one hundred eleven billion, two hundred sixty-three million, one hundred twenty-four thousand, five hundred forty-three".