Base | Representation |
---|---|
bin | 11001000011111110101100… |
… | …10010111100001011110111 |
3 | 21020010200112101102022220011 |
4 | 30201333112102330023313 |
5 | 24210430013042224221 |
6 | 313114130043321051 |
7 | 14415506453162011 |
oct | 1441772622741367 |
9 | 236120471368804 |
10 | 55112320664311 |
11 | 16619005270149 |
12 | 6221178820187 |
13 | 249a0b9a12b91 |
14 | d876444611b1 |
15 | 6588e807d1e1 |
hex | 321fd64bc2f7 |
55112320664311 has 4 divisors (see below), whose sum is σ = 55113796779552. Its totient is φ = 55110844549072.
The previous prime is 55112320664263. The next prime is 55112320664351. The reversal of 55112320664311 is 11346602321155.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55112320664311 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55112320664351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 738001615 + ... + 738076288.
It is an arithmetic number, because the mean of its divisors is an integer number (13778449194888).
Almost surely, 255112320664311 is an apocalyptic number.
55112320664311 is a deficient number, since it is larger than the sum of its proper divisors (1476115241).
55112320664311 is a wasteful number, since it uses less digits than its factorization.
55112320664311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1476115240.
The product of its (nonzero) digits is 129600, while the sum is 40.
Adding to 55112320664311 its reverse (11346602321155), we get a palindrome (66458922985466).
The spelling of 55112320664311 in words is "fifty-five trillion, one hundred twelve billion, three hundred twenty million, six hundred sixty-four thousand, three hundred eleven".
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