Base | Representation |
---|---|
bin | 100000110110011… |
… | …001001111000001 |
3 | 1102102001022022001 |
4 | 200312121033001 |
5 | 2112042130144 |
6 | 130404344001 |
7 | 16441346101 |
oct | 4066311701 |
9 | 1372038261 |
10 | 551130049 |
11 | 26310a188 |
12 | 1346a5001 |
13 | 8a247972 |
14 | 532a5201 |
15 | 335b7bd4 |
hex | 20d993c1 |
551130049 has 4 divisors (see below), whose sum is σ = 552060036. Its totient is φ = 550200064.
The previous prime is 551130029. The next prime is 551130061. The reversal of 551130049 is 940031155.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 232257600 + 318872449 = 15240^2 + 17857^2 .
It is a cyclic number.
It is not a de Polignac number, because 551130049 - 217 = 550998977 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 551129999 and 551130026.
It is not an unprimeable number, because it can be changed into a prime (551130029) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 464104 + ... + 465289.
It is an arithmetic number, because the mean of its divisors is an integer number (138015009).
Almost surely, 2551130049 is an apocalyptic number.
It is an amenable number.
551130049 is a deficient number, since it is larger than the sum of its proper divisors (929987).
551130049 is an equidigital number, since it uses as much as digits as its factorization.
551130049 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 929986.
The product of its (nonzero) digits is 2700, while the sum is 28.
The square root of 551130049 is about 23476.1591620094. The cubic root of 551130049 is about 819.8820219916.
The spelling of 551130049 in words is "five hundred fifty-one million, one hundred thirty thousand, forty-nine".
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