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55114121 is a prime number
BaseRepresentation
bin1101001000111…
…1100110001001
310211201002100202
43102033212021
5103102122441
65245141545
71236314366
oct322174611
9124632322
1055114121
1129124067
121655a8b5
13b55910a
14746946d
154c8a19b
hex348f989

55114121 has 2 divisors, whose sum is σ = 55114122. Its totient is φ = 55114120.

The previous prime is 55114109. The next prime is 55114159. The reversal of 55114121 is 12141155.

55114121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 52345225 + 2768896 = 7235^2 + 1664^2 .

It is a cyclic number.

It is not a de Polignac number, because 55114121 - 218 = 54851977 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 55114093 and 55114102.

It is not a weakly prime, because it can be changed into another prime (55114921) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27557060 + 27557061.

It is an arithmetic number, because the mean of its divisors is an integer number (27557061).

Almost surely, 255114121 is an apocalyptic number.

It is an amenable number.

55114121 is a deficient number, since it is larger than the sum of its proper divisors (1).

55114121 is an equidigital number, since it uses as much as digits as its factorization.

55114121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 200, while the sum is 20.

The square root of 55114121 is about 7423.8885363400. Note that the first 3 decimals coincide. The cubic root of 55114121 is about 380.5580926899.

Adding to 55114121 its reverse (12141155), we get a palindrome (67255276).

The spelling of 55114121 in words is "fifty-five million, one hundred fourteen thousand, one hundred twenty-one".