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55122011143 = 199357276499
BaseRepresentation
bin110011010101100001…
…110010010000000111
312021021112210022000021
4303111201302100013
51400342213324033
641153412000011
73660655235563
oct632541622007
9167245708007
1055122011143
1121416a35911
12a824300007
135275c7aa54
14294cab26a3
15167939cb2d
hexcd5872407

55122011143 has 4 divisors (see below), whose sum is σ = 55122487000. Its totient is φ = 55121535288.

The previous prime is 55122011137. The next prime is 55122011167. The reversal of 55122011143 is 34111022155.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 55122011143 - 221 = 55119913991 is a prime.

It is a super-2 number, since 2×551220111432 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55122011843) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61108 + ... + 337606.

It is an arithmetic number, because the mean of its divisors is an integer number (13780621750).

Almost surely, 255122011143 is an apocalyptic number.

55122011143 is a deficient number, since it is larger than the sum of its proper divisors (475857).

55122011143 is a wasteful number, since it uses less digits than its factorization.

55122011143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 475856.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 55122011143 its reverse (34111022155), we get a palindrome (89233033298).

The spelling of 55122011143 in words is "fifty-five billion, one hundred twenty-two million, eleven thousand, one hundred forty-three".

Divisors: 1 199357 276499 55122011143