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551221400200351 = 1973279382361987
BaseRepresentation
bin111110101010101010011101…
…1110000000110010010011111
32200021201020210010200211120211
41331111110323300012102133
51034222202411422402401
65232203340532153251
7224051301105114526
oct17525247360062237
92607636703624524
10551221400200351
1114a6aa757112241
12519a6497768827
131a875c55197cba
149a193883d94bd
1543ad800d98951
hex1f5553bc0649f

551221400200351 has 4 divisors (see below), whose sum is σ = 551500782564312. Its totient is φ = 550942017836392.

The previous prime is 551221400200333. The next prime is 551221400200391. The reversal of 551221400200351 is 153002004122155.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 551221400200351 - 223 = 551221391811743 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (551221400200301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139691179021 + ... + 139691182966.

It is an arithmetic number, because the mean of its divisors is an integer number (137875195641078).

Almost surely, 2551221400200351 is an apocalyptic number.

551221400200351 is a deficient number, since it is larger than the sum of its proper divisors (279382363961).

551221400200351 is a wasteful number, since it uses less digits than its factorization.

551221400200351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 279382363960.

The product of its (nonzero) digits is 12000, while the sum is 31.

The spelling of 551221400200351 in words is "five hundred fifty-one trillion, two hundred twenty-one billion, four hundred million, two hundred thousand, three hundred fifty-one".

Divisors: 1 1973 279382361987 551221400200351