Base | Representation |
---|---|
bin | 10000000010101111110… |
… | …01001010000111100011 |
3 | 1221200211012021110101120 |
4 | 20001113321022013203 |
5 | 33012404441242311 |
6 | 1101122020503323 |
7 | 54553001135661 |
oct | 10012771120743 |
9 | 1850735243346 |
10 | 551230415331 |
11 | 1a2859220822 |
12 | 8a9b9b4ab43 |
13 | 3cc99aa0cbb |
14 | 1c97311dc31 |
15 | e513520706 |
hex | 8057e4a1e3 |
551230415331 has 16 divisors (see below), whose sum is σ = 791668930560. Its totient is φ = 340170240960.
The previous prime is 551230415327. The next prime is 551230415341. The reversal of 551230415331 is 133514032155.
It is not a de Polignac number, because 551230415331 - 22 = 551230415327 is a prime.
It is a super-2 number, since 2×5512304153312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 551230415292 and 551230415301.
It is not an unprimeable number, because it can be changed into a prime (551230415341) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 128850226 + ... + 128854503.
It is an arithmetic number, because the mean of its divisors is an integer number (49479308160).
Almost surely, 2551230415331 is an apocalyptic number.
551230415331 is a deficient number, since it is larger than the sum of its proper divisors (240438515229).
551230415331 is a wasteful number, since it uses less digits than its factorization.
551230415331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 257704786.
The product of its (nonzero) digits is 27000, while the sum is 33.
Adding to 551230415331 its reverse (133514032155), we get a palindrome (684744447486).
The spelling of 551230415331 in words is "five hundred fifty-one billion, two hundred thirty million, four hundred fifteen thousand, three hundred thirty-one".
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