Base | Representation |
---|---|
bin | 110011010101110010… |
… | …100100111101011101 |
3 | 12021021212001221102112 |
4 | 303111302210331131 |
5 | 1400344330210044 |
6 | 41154050203405 |
7 | 3661040531453 |
oct | 632562447535 |
9 | 167255057375 |
10 | 55126413149 |
11 | 21419472135 |
12 | a825883565 |
13 | 5276b5c5a2 |
14 | 294d4da9d3 |
15 | 167996c09e |
hex | cd5ca4f5d |
55126413149 has 2 divisors, whose sum is σ = 55126413150. Its totient is φ = 55126413148.
The previous prime is 55126413143. The next prime is 55126413227. The reversal of 55126413149 is 94131462155.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 53618644249 + 1507768900 = 231557^2 + 38830^2 .
It is a cyclic number.
It is not a de Polignac number, because 55126413149 - 232 = 50831445853 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55126413143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27563206574 + 27563206575.
It is an arithmetic number, because the mean of its divisors is an integer number (27563206575).
Almost surely, 255126413149 is an apocalyptic number.
It is an amenable number.
55126413149 is a deficient number, since it is larger than the sum of its proper divisors (1).
55126413149 is an equidigital number, since it uses as much as digits as its factorization.
55126413149 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 129600, while the sum is 41.
The spelling of 55126413149 in words is "fifty-five billion, one hundred twenty-six million, four hundred thirteen thousand, one hundred forty-nine".
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