Base | Representation |
---|---|
bin | 101000000111001111100… |
… | …0010000111110100000111 |
3 | 201112001022012022111201211 |
4 | 1100032133002013310013 |
5 | 1210311322430040112 |
6 | 15420404401432251 |
7 | 1106211014532004 |
oct | 120163702076407 |
9 | 21461265274654 |
10 | 5513111174407 |
11 | 1836108593391 |
12 | 75058993b687 |
13 | 30cb6563a7b5 |
14 | 150b9bdd48ab |
15 | 9861e4170a7 |
hex | 5039f087d07 |
5513111174407 has 2 divisors, whose sum is σ = 5513111174408. Its totient is φ = 5513111174406.
The previous prime is 5513111174387. The next prime is 5513111174471. The reversal of 5513111174407 is 7044711113155.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5513111174407 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5513111174407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5513111174507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2756555587203 + 2756555587204.
It is an arithmetic number, because the mean of its divisors is an integer number (2756555587204).
Almost surely, 25513111174407 is an apocalyptic number.
5513111174407 is a deficient number, since it is larger than the sum of its proper divisors (1).
5513111174407 is an equidigital number, since it uses as much as digits as its factorization.
5513111174407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 58800, while the sum is 40.
The spelling of 5513111174407 in words is "five trillion, five hundred thirteen billion, one hundred eleven million, one hundred seventy-four thousand, four hundred seven".
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