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551311500253 is a prime number
BaseRepresentation
bin10000000010111001011…
…10011110001111011101
31221201000211211222222211
420001130232132033131
533013041221002003
61101134034440421
754555004301113
oct10013456361735
91851024758884
10551311500253
111a289aa73058
128aa21133111
133ccb0821147
141c97dbc9ab3
15e51a6da96d
hex805cb9e3dd

551311500253 has 2 divisors, whose sum is σ = 551311500254. Its totient is φ = 551311500252.

The previous prime is 551311500247. The next prime is 551311500263. The reversal of 551311500253 is 352005113155.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 509222105604 + 42089394649 = 713598^2 + 205157^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-551311500253 is a prime.

It is a super-3 number, since 3×5513115002533 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (551311500263) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275655750126 + 275655750127.

It is an arithmetic number, because the mean of its divisors is an integer number (275655750127).

Almost surely, 2551311500253 is an apocalyptic number.

It is an amenable number.

551311500253 is a deficient number, since it is larger than the sum of its proper divisors (1).

551311500253 is an equidigital number, since it uses as much as digits as its factorization.

551311500253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11250, while the sum is 31.

The spelling of 551311500253 in words is "five hundred fifty-one billion, three hundred eleven million, five hundred thousand, two hundred fifty-three".