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5513230322401 is a prime number
BaseRepresentation
bin101000000111010011000…
…1000101000101011100001
3201112001121111111212001111
41100032212020220223201
51210312043430304101
615420424255303321
71106213662344154
oct120164610505341
921461544455044
105513230322401
111836169872aaa
1275060181ab41
1330cb84226979
14150badb6bc9b
1598629b00251
hex503a6228ae1

5513230322401 has 2 divisors, whose sum is σ = 5513230322402. Its totient is φ = 5513230322400.

The previous prime is 5513230322389. The next prime is 5513230322473. The reversal of 5513230322401 is 1042230323155.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4286042716176 + 1227187606225 = 2070276^2 + 1107785^2 .

It is a cyclic number.

It is not a de Polignac number, because 5513230322401 - 27 = 5513230322273 is a prime.

It is a super-3 number, since 3×55132303224013 (a number of 39 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (5513230320401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2756615161200 + 2756615161201.

It is an arithmetic number, because the mean of its divisors is an integer number (2756615161201).

Almost surely, 25513230322401 is an apocalyptic number.

It is an amenable number.

5513230322401 is a deficient number, since it is larger than the sum of its proper divisors (1).

5513230322401 is an equidigital number, since it uses as much as digits as its factorization.

5513230322401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 5513230322401 its reverse (1042230323155), we get a palindrome (6555460645556).

The spelling of 5513230322401 in words is "five trillion, five hundred thirteen billion, two hundred thirty million, three hundred twenty-two thousand, four hundred one".