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5513243514047 is a prime number
BaseRepresentation
bin101000000111010011011…
…1010111101010010111111
3201112001122102100001120222
41100032212322331102333
51210312110314422142
615420425450131555
71106214212435603
oct120164672752277
921461572301528
105513243514047
111836176263095
12750606120bbb
1330cb86b95189
14150bb1803503
159862ad58bd2
hex503a6ebd4bf

5513243514047 has 2 divisors, whose sum is σ = 5513243514048. Its totient is φ = 5513243514046.

The previous prime is 5513243513957. The next prime is 5513243514151. The reversal of 5513243514047 is 7404153423155.

5513243514047 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5513243514047 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5513243513989 and 5513243514007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5513243714047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2756621757023 + 2756621757024.

It is an arithmetic number, because the mean of its divisors is an integer number (2756621757024).

Almost surely, 25513243514047 is an apocalyptic number.

5513243514047 is a deficient number, since it is larger than the sum of its proper divisors (1).

5513243514047 is an equidigital number, since it uses as much as digits as its factorization.

5513243514047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008000, while the sum is 44.

The spelling of 5513243514047 in words is "five trillion, five hundred thirteen billion, two hundred forty-three million, five hundred fourteen thousand, forty-seven".