Base | Representation |
---|---|
bin | 11001000100100111111000… |
… | …10100011111110101010011 |
3 | 21020012210121110111212212012 |
4 | 30202103330110133311103 |
5 | 24211310304430140110 |
6 | 313132224205053135 |
7 | 14420221441535003 |
oct | 1442237424376523 |
9 | 236183543455765 |
10 | 55134433443155 |
11 | 16627422366190 |
12 | 622550a2571ab |
13 | 249c202030cc1 |
14 | d8874119c003 |
15 | 65928e537905 |
hex | 3224fc51fd53 |
55134433443155 has 16 divisors (see below), whose sum is σ = 73854496894464. Its totient is φ = 39165263501280.
The previous prime is 55134433443109. The next prime is 55134433443179.
55134433443155 is nontrivially palindromic in base 10.
It is a de Polignac number, because none of the positive numbers 2k-55134433443155 is a prime.
It is a super-3 number, since 3×551344334431553 (a number of 42 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11656326059 + ... + 11656330788.
It is an arithmetic number, because the mean of its divisors is an integer number (4615906055904).
Almost surely, 255134433443155 is an apocalyptic number.
55134433443155 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
55134433443155 is a deficient number, since it is larger than the sum of its proper divisors (18720063451309).
55134433443155 is a wasteful number, since it uses less digits than its factorization.
55134433443155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23312656906.
The product of its digits is 12960000, while the sum is 50.
It can be divided in two parts, 5513443 and 3443155, that added together give a palindrome (8956598).
The spelling of 55134433443155 in words is "fifty-five trillion, one hundred thirty-four billion, four hundred thirty-three million, four hundred forty-three thousand, one hundred fifty-five".
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