Base | Representation |
---|---|
bin | 10000000010111110100… |
… | …01110010011110000101 |
3 | 1221201010211102002110121 |
4 | 20001133101302132011 |
5 | 33013133201000311 |
6 | 1101142204221541 |
7 | 54556034221312 |
oct | 10013721623605 |
9 | 1851124362417 |
10 | 551354312581 |
11 | 1a2912154646 |
12 | 8aa3353a8b1 |
13 | 3ccb9660a97 |
14 | 1c985771d09 |
15 | e51e345b71 |
hex | 805f472785 |
551354312581 has 2 divisors, whose sum is σ = 551354312582. Its totient is φ = 551354312580.
The previous prime is 551354312549. The next prime is 551354312599. The reversal of 551354312581 is 185213453155.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 484681908481 + 66672404100 = 696191^2 + 258210^2 .
It is a cyclic number.
It is not a de Polignac number, because 551354312581 - 25 = 551354312549 is a prime.
It is a super-2 number, since 2×5513543125812 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (551354312381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275677156290 + 275677156291.
It is an arithmetic number, because the mean of its divisors is an integer number (275677156291).
Almost surely, 2551354312581 is an apocalyptic number.
It is an amenable number.
551354312581 is a deficient number, since it is larger than the sum of its proper divisors (1).
551354312581 is an equidigital number, since it uses as much as digits as its factorization.
551354312581 is an evil number, because the sum of its binary digits is even.
The product of its digits is 360000, while the sum is 43.
The spelling of 551354312581 in words is "five hundred fifty-one billion, three hundred fifty-four million, three hundred twelve thousand, five hundred eighty-one".
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