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55136254013 is a prime number
BaseRepresentation
bin110011010110011000…
…000111100000111101
312021022112120220112222
4303112120013200331
51400404340112023
641155041135125
73661220266151
oct632630074075
9167275526488
1055136254013
1121423a83785
12a82902a4a5
135278bc6899
14295093d061
15167a762cc8
hexcd660783d

55136254013 has 2 divisors, whose sum is σ = 55136254014. Its totient is φ = 55136254012.

The previous prime is 55136254007. The next prime is 55136254057. The reversal of 55136254013 is 31045263155.

55136254013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 53244178009 + 1892076004 = 230747^2 + 43498^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55136254013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55136254213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27568127006 + 27568127007.

It is an arithmetic number, because the mean of its divisors is an integer number (27568127007).

Almost surely, 255136254013 is an apocalyptic number.

It is an amenable number.

55136254013 is a deficient number, since it is larger than the sum of its proper divisors (1).

55136254013 is an equidigital number, since it uses as much as digits as its factorization.

55136254013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54000, while the sum is 35.

It can be divided in two parts, 5513 and 6254013, that added together give a palindrome (6259526).

The spelling of 55136254013 in words is "fifty-five billion, one hundred thirty-six million, two hundred fifty-four thousand, thirteen".