Base | Representation |
---|---|
bin | 11001000100101011110110… |
… | …11011101010100000001111 |
3 | 21020020000010002100102201022 |
4 | 30202111323123222200033 |
5 | 24211324141400401203 |
6 | 313133215545504355 |
7 | 14420325335315264 |
oct | 1442257333524017 |
9 | 236200102312638 |
10 | 55136566028303 |
11 | 1662831712aa51 |
12 | 6225a044a20bb |
13 | 249c481aba6c6 |
14 | d888a44cb26b |
15 | 659366889a38 |
hex | 32257b6ea80f |
55136566028303 has 2 divisors, whose sum is σ = 55136566028304. Its totient is φ = 55136566028302.
The previous prime is 55136566028261. The next prime is 55136566028311. The reversal of 55136566028303 is 30382066563155.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55136566028303 - 212 = 55136566024207 is a prime.
It is a super-3 number, since 3×551365660283033 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55136566022303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27568283014151 + 27568283014152.
It is an arithmetic number, because the mean of its divisors is an integer number (27568283014152).
Almost surely, 255136566028303 is an apocalyptic number.
55136566028303 is a deficient number, since it is larger than the sum of its proper divisors (1).
55136566028303 is an equidigital number, since it uses as much as digits as its factorization.
55136566028303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664000, while the sum is 53.
The spelling of 55136566028303 in words is "fifty-five trillion, one hundred thirty-six billion, five hundred sixty-six million, twenty-eight thousand, three hundred three".
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