Base | Representation |
---|---|
bin | 111110101100010000111000… |
… | …1001100010101000011011010 |
3 | 2200022111021111010110122222212 |
4 | 1331120201301030111003122 |
5 | 1034234303331033003102 |
6 | 5232452353204115122 |
7 | 224103215321460026 |
oct | 17530416114250332 |
9 | 2608437433418885 |
10 | 551441340125402 |
11 | 14a784a60500241 |
12 | 51a21039095aa2 |
13 | 1a8909065b999c |
14 | 9a25c90805386 |
15 | 43b43c4b6dc52 |
hex | 1f588713150da |
551441340125402 has 8 divisors (see below), whose sum is σ = 827363217208512. Its totient is φ = 275653601055900.
The previous prime is 551441340125381. The next prime is 551441340125443. The reversal of 551441340125402 is 204521043144155.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a self number, because there is not a number n which added to its sum of digits gives 551441340125402.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33534493124 + ... + 33534509567.
It is an arithmetic number, because the mean of its divisors is an integer number (103420402151064).
Almost surely, 2551441340125402 is an apocalyptic number.
551441340125402 is a deficient number, since it is larger than the sum of its proper divisors (275921877083110).
551441340125402 is a wasteful number, since it uses less digits than its factorization.
551441340125402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67069006804.
The product of its (nonzero) digits is 384000, while the sum is 41.
Adding to 551441340125402 its reverse (204521043144155), we get a palindrome (755962383269557).
The spelling of 551441340125402 in words is "five hundred fifty-one trillion, four hundred forty-one billion, three hundred forty million, one hundred twenty-five thousand, four hundred two".
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