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5515103999981 is a prime number
BaseRepresentation
bin101000001000001010111…
…0100001001011111101101
3201112020110002011112111102
41100100111310021133231
51210324413110444411
615421334230532445
71106311263343052
oct120202564113755
921466402145442
105515103999981
111836a4047a774
12750a45207125
133100c2472424
14150d0a943029
15986d935dd3b
hex50415d097ed

5515103999981 has 2 divisors, whose sum is σ = 5515103999982. Its totient is φ = 5515103999980.

The previous prime is 5515103999953. The next prime is 5515104000023. The reversal of 5515103999981 is 1899993015155.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4103501004100 + 1411602995881 = 2025710^2 + 1188109^2 .

It is a cyclic number.

It is not a de Polignac number, because 5515103999981 - 218 = 5515103737837 is a prime.

It is a super-2 number, since 2×55151039999812 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5515103909981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2757551999990 + 2757551999991.

It is an arithmetic number, because the mean of its divisors is an integer number (2757551999991).

Almost surely, 25515103999981 is an apocalyptic number.

It is an amenable number.

5515103999981 is a deficient number, since it is larger than the sum of its proper divisors (1).

5515103999981 is an equidigital number, since it uses as much as digits as its factorization.

5515103999981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19683000, while the sum is 65.

The spelling of 5515103999981 in words is "five trillion, five hundred fifteen billion, one hundred three million, nine hundred ninety-nine thousand, nine hundred eighty-one".