Base | Representation |
---|---|
bin | 101000001000010100110… |
… | …0111111100011101000011 |
3 | 201112021022020112102100221 |
4 | 1100100221213330131003 |
5 | 1210331103201021110 |
6 | 15421431222123511 |
7 | 1106322440256322 |
oct | 120205147743503 |
9 | 21467266472327 |
10 | 5515436345155 |
11 | 18370a1036600 |
12 | 750b18580597 |
13 | 310146286789 |
14 | 150d3cb360b9 |
15 | 9870860b7da |
hex | 504299fc743 |
5515436345155 has 48 divisors (see below), whose sum is σ = 7294346589600. Its totient is φ = 4000515706880.
The previous prime is 5515436345099. The next prime is 5515436345171.
5515436345155 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 5515436345155 - 29 = 5515436344643 is a prime.
It is a super-3 number, since 3×55154363451553 (a number of 39 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1187901264 + ... + 1187905906.
It is an arithmetic number, because the mean of its divisors is an integer number (151965553950).
Almost surely, 25515436345155 is an apocalyptic number.
5515436345155 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
5515436345155 is a deficient number, since it is larger than the sum of its proper divisors (1778910244445).
5515436345155 is a wasteful number, since it uses less digits than its factorization.
5515436345155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9492 (or 9481 counting only the distinct ones).
The product of its digits is 13500000, while the sum is 52.
The spelling of 5515436345155 in words is "five trillion, five hundred fifteen billion, four hundred thirty-six million, three hundred forty-five thousand, one hundred fifty-five".
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