Base | Representation |
---|---|
bin | 110011011000100011… |
… | …111011110001110101 |
3 | 12021102002120000202201 |
4 | 303120203323301311 |
5 | 1400443230443401 |
6 | 41202430504501 |
7 | 3662143651435 |
oct | 633043736165 |
9 | 167362500681 |
10 | 55172906101 |
11 | 21442737a65 |
12 | a839365131 |
13 | 528368a601 |
14 | 29557602c5 |
15 | 167daa2b01 |
hex | cd88fbc75 |
55172906101 has 2 divisors, whose sum is σ = 55172906102. Its totient is φ = 55172906100.
The previous prime is 55172906017. The next prime is 55172906167. The reversal of 55172906101 is 10160927155.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 46256825476 + 8916080625 = 215074^2 + 94425^2 .
It is a cyclic number.
It is not a de Polignac number, because 55172906101 - 27 = 55172905973 is a prime.
It is a super-3 number, since 3×551729061013 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55172706101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27586453050 + 27586453051.
It is an arithmetic number, because the mean of its divisors is an integer number (27586453051).
Almost surely, 255172906101 is an apocalyptic number.
It is an amenable number.
55172906101 is a deficient number, since it is larger than the sum of its proper divisors (1).
55172906101 is an equidigital number, since it uses as much as digits as its factorization.
55172906101 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18900, while the sum is 37.
The spelling of 55172906101 in words is "fifty-five billion, one hundred seventy-two million, nine hundred six thousand, one hundred one".
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