Base | Representation |
---|---|
bin | 110011011010001111… |
… | …000111100101001101 |
3 | 12021111001102112122012 |
4 | 303122033013211031 |
5 | 1401022424110403 |
6 | 41205313031005 |
7 | 3662634535202 |
oct | 633217074515 |
9 | 167431375565 |
10 | 55201003853 |
11 | 21457589246 |
12 | a846855465 |
13 | 52894477b8 |
14 | 2959395ca9 |
15 | 16812a2ed8 |
hex | cda3c794d |
55201003853 has 2 divisors, whose sum is σ = 55201003854. Its totient is φ = 55201003852.
The previous prime is 55201003849. The next prime is 55201003889. The reversal of 55201003853 is 35830010255.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52119976804 + 3081027049 = 228298^2 + 55507^2 .
It is a cyclic number.
It is not a de Polignac number, because 55201003853 - 22 = 55201003849 is a prime.
It is a super-3 number, since 3×552010038533 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55201003843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27600501926 + 27600501927.
It is an arithmetic number, because the mean of its divisors is an integer number (27600501927).
Almost surely, 255201003853 is an apocalyptic number.
It is an amenable number.
55201003853 is a deficient number, since it is larger than the sum of its proper divisors (1).
55201003853 is an equidigital number, since it uses as much as digits as its factorization.
55201003853 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18000, while the sum is 32.
The spelling of 55201003853 in words is "fifty-five billion, two hundred one million, three thousand, eight hundred fifty-three".
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