Base | Representation |
---|---|
bin | 100000111001110… |
… | …001110010111011 |
3 | 1102110201101002011 |
4 | 200321301302323 |
5 | 2112304021313 |
6 | 130435350351 |
7 | 16452032152 |
oct | 4071616273 |
9 | 1373641064 |
10 | 552017083 |
11 | 263665672 |
12 | 134a523b7 |
13 | 8a498637 |
14 | 53456599 |
15 | 336e093d |
hex | 20e71cbb |
552017083 has 4 divisors (see below), whose sum is σ = 552193480. Its totient is φ = 551840688.
The previous prime is 552017077. The next prime is 552017111. The reversal of 552017083 is 380710255.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 380710255 = 5 ⋅76142051.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-552017083 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (552017483) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83418 + ... + 89791.
It is an arithmetic number, because the mean of its divisors is an integer number (138048370).
Almost surely, 2552017083 is an apocalyptic number.
552017083 is a deficient number, since it is larger than the sum of its proper divisors (176397).
552017083 is a wasteful number, since it uses less digits than its factorization.
552017083 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 176396.
The product of its (nonzero) digits is 8400, while the sum is 31.
The square root of 552017083 is about 23495.0437965116. The cubic root of 552017083 is about 820.3216480574.
The spelling of 552017083 in words is "five hundred fifty-two million, seventeen thousand, eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •