Base | Representation |
---|---|
bin | 11001000110101000010000… |
… | …11001111100111001110011 |
3 | 21020110101111202212002111221 |
4 | 30203110020121330321303 |
5 | 24213422433023120100 |
6 | 313224023235445511 |
7 | 14425211421051112 |
oct | 1443241031747163 |
9 | 236411452762457 |
10 | 55203355676275 |
11 | 16653680149024 |
12 | 6236944156897 |
13 | 24a58670b0671 |
14 | d8bbdc9c1c79 |
15 | 65ae7520501a |
hex | 32350867ce73 |
55203355676275 has 24 divisors (see below), whose sum is σ = 69261377367600. Its totient is φ = 43643618578560.
The previous prime is 55203355676269. The next prime is 55203355676299. The reversal of 55203355676275 is 57267655330255.
55203355676275 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 55203355676275 - 25 = 55203355676243 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 36879609 + ... + 38347258.
It is an arithmetic number, because the mean of its divisors is an integer number (2885890723650).
Almost surely, 255203355676275 is an apocalyptic number.
55203355676275 is a deficient number, since it is larger than the sum of its proper divisors (14058021691325).
55203355676275 is a wasteful number, since it uses less digits than its factorization.
55203355676275 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 75227223 (or 75227218 counting only the distinct ones).
The product of its (nonzero) digits is 198450000, while the sum is 61.
The spelling of 55203355676275 in words is "fifty-five trillion, two hundred three billion, three hundred fifty-five million, six hundred seventy-six thousand, two hundred seventy-five".
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