Base | Representation |
---|---|
bin | 111110110000101010000010… |
… | …1111100011111111000111111 |
3 | 2200101121222222100220101001120 |
4 | 1331201110011330133320333 |
5 | 1034324201412041431421 |
6 | 5234034010542242023 |
7 | 224164641660110601 |
oct | 17541240574377077 |
9 | 2611558870811046 |
10 | 552045131202111 |
11 | 14a99803085a888 |
12 | 51aba065586313 |
13 | 1a90582b7a8b41 |
14 | 9a471ac377171 |
15 | 43c4e627438c6 |
hex | 1f61505f1fe3f |
552045131202111 has 8 divisors (see below), whose sum is σ = 736292590539264. Its totient is φ = 367913879666520.
The previous prime is 552045131202109. The next prime is 552045131202137. The reversal of 552045131202111 is 111202131540255.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 552045131202111 - 21 = 552045131202109 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (552045131202161) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29051939305 + ... + 29051958306.
It is an arithmetic number, because the mean of its divisors is an integer number (92036573817408).
Almost surely, 2552045131202111 is an apocalyptic number.
552045131202111 is a deficient number, since it is larger than the sum of its proper divisors (184247459337153).
552045131202111 is a wasteful number, since it uses less digits than its factorization.
552045131202111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58103900781.
The product of its (nonzero) digits is 12000, while the sum is 33.
Adding to 552045131202111 its reverse (111202131540255), we get a palindrome (663247262742366).
The spelling of 552045131202111 in words is "five hundred fifty-two trillion, forty-five billion, one hundred thirty-one million, two hundred two thousand, one hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •