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552055034981 is a prime number
BaseRepresentation
bin10000000100010010000…
…10110101010001100101
31221202221122221110220002
420002021002311101211
533021102042104411
61101335515151045
754612303241622
oct10021102652145
91852848843802
10552055034981
111a314174776a
128abaa145485
134009b893c18
141ca10857349
15e560b0c33b
hex80890b5465

552055034981 has 2 divisors, whose sum is σ = 552055034982. Its totient is φ = 552055034980.

The previous prime is 552055034977. The next prime is 552055035011. The reversal of 552055034981 is 189430550255.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 289157854756 + 262897180225 = 537734^2 + 512735^2 .

It is a cyclic number.

It is not a de Polignac number, because 552055034981 - 22 = 552055034977 is a prime.

It is a super-3 number, since 3×5520550349813 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (552055034081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276027517490 + 276027517491.

It is an arithmetic number, because the mean of its divisors is an integer number (276027517491).

Almost surely, 2552055034981 is an apocalyptic number.

It is an amenable number.

552055034981 is a deficient number, since it is larger than the sum of its proper divisors (1).

552055034981 is an equidigital number, since it uses as much as digits as its factorization.

552055034981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1080000, while the sum is 47.

The spelling of 552055034981 in words is "five hundred fifty-two billion, fifty-five million, thirty-four thousand, nine hundred eighty-one".