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5520733647053 = 31178088182163
BaseRepresentation
bin101000001010110010101…
…0111100011000011001101
3201112202222102100020110112
41100111211113203003031
51210422430303201203
615424105013445405
71106600632505222
oct120254527430315
921482872306415
105520733647053
11183936a244959
12751b56640865
133107ab8aa041
141512c24a7949
15989186dc6d8
hex505655e30cd

5520733647053 has 4 divisors (see below), whose sum is σ = 5698821829248. Its totient is φ = 5342645464860.

The previous prime is 5520733646999. The next prime is 5520733647083. The reversal of 5520733647053 is 3507463370255.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5520733647053 - 242 = 1122687135949 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5520733646992 and 5520733647010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5520733647083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89044091051 + ... + 89044091112.

It is an arithmetic number, because the mean of its divisors is an integer number (1424705457312).

Almost surely, 25520733647053 is an apocalyptic number.

It is an amenable number.

5520733647053 is a deficient number, since it is larger than the sum of its proper divisors (178088182195).

5520733647053 is a wasteful number, since it uses less digits than its factorization.

5520733647053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 178088182194.

The product of its (nonzero) digits is 7938000, while the sum is 50.

The spelling of 5520733647053 in words is "five trillion, five hundred twenty billion, seven hundred thirty-three million, six hundred forty-seven thousand, fifty-three".

Divisors: 1 31 178088182163 5520733647053