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55211045403 = 318403681801
BaseRepresentation
bin110011011010110101…
…011011001000011011
312021111202022201001110
4303122311123020123
51401033011423103
641210312151403
73663116066643
oct633265331033
9167452281043
1055211045403
1121462217648
12a84a098563
13528b552247
14295a84b523
1516820d8403
hexcdad5b21b

55211045403 has 4 divisors (see below), whose sum is σ = 73614727208. Its totient is φ = 36807363600.

The previous prime is 55211045389. The next prime is 55211045413. The reversal of 55211045403 is 30454011255.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 55211045403 - 24 = 55211045387 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55211045413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9201840898 + ... + 9201840903.

It is an arithmetic number, because the mean of its divisors is an integer number (18403681802).

Almost surely, 255211045403 is an apocalyptic number.

55211045403 is a deficient number, since it is larger than the sum of its proper divisors (18403681805).

55211045403 is a wasteful number, since it uses less digits than its factorization.

55211045403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18403681804.

The product of its (nonzero) digits is 12000, while the sum is 30.

Adding to 55211045403 its reverse (30454011255), we get a palindrome (85665056658).

The spelling of 55211045403 in words is "fifty-five billion, two hundred eleven million, forty-five thousand, four hundred three".

Divisors: 1 3 18403681801 55211045403