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5521105035147 = 313210889753521
BaseRepresentation
bin101000001010111101110…
…0000010001111110001011
3201112210221022011201011010
41100111323200101332023
51210424210342111042
615424205521535003
71106613062322312
oct120257340217613
921483838151133
105521105035147
11183953a948269
1275203aaa4463
1331083a811400
14151319941279
159893b0ed59c
hex5057b811f8b

5521105035147 has 12 divisors (see below), whose sum is σ = 7971299578104. Its totient is φ = 3397603098240.

The previous prime is 5521105035091. The next prime is 5521105035169. The reversal of 5521105035147 is 7415305011255.

It is not a de Polignac number, because 5521105035147 - 211 = 5521105033099 is a prime.

It is a super-2 number, since 2×55211050351472 (a number of 26 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (39).

It is not an unprimeable number, because it can be changed into a prime (5521105031147) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5444876254 + ... + 5444877267.

It is an arithmetic number, because the mean of its divisors is an integer number (664274964842).

Almost surely, 25521105035147 is an apocalyptic number.

5521105035147 is a deficient number, since it is larger than the sum of its proper divisors (2450194542957).

5521105035147 is a wasteful number, since it uses less digits than its factorization.

5521105035147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10889753550 (or 10889753537 counting only the distinct ones).

The product of its (nonzero) digits is 105000, while the sum is 39.

The spelling of 5521105035147 in words is "five trillion, five hundred twenty-one billion, one hundred five million, thirty-five thousand, one hundred forty-seven".

Divisors: 1 3 13 39 169 507 10889753521 32669260563 141566795773 424700387319 1840368345049 5521105035147