Base | Representation |
---|---|
bin | 101000001010111101110… |
… | …0000010001111110001011 |
3 | 201112210221022011201011010 |
4 | 1100111323200101332023 |
5 | 1210424210342111042 |
6 | 15424205521535003 |
7 | 1106613062322312 |
oct | 120257340217613 |
9 | 21483838151133 |
10 | 5521105035147 |
11 | 183953a948269 |
12 | 75203aaa4463 |
13 | 31083a811400 |
14 | 151319941279 |
15 | 9893b0ed59c |
hex | 5057b811f8b |
5521105035147 has 12 divisors (see below), whose sum is σ = 7971299578104. Its totient is φ = 3397603098240.
The previous prime is 5521105035091. The next prime is 5521105035169. The reversal of 5521105035147 is 7415305011255.
It is not a de Polignac number, because 5521105035147 - 211 = 5521105033099 is a prime.
It is a super-2 number, since 2×55211050351472 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is not an unprimeable number, because it can be changed into a prime (5521105031147) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5444876254 + ... + 5444877267.
It is an arithmetic number, because the mean of its divisors is an integer number (664274964842).
Almost surely, 25521105035147 is an apocalyptic number.
5521105035147 is a deficient number, since it is larger than the sum of its proper divisors (2450194542957).
5521105035147 is a wasteful number, since it uses less digits than its factorization.
5521105035147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10889753550 (or 10889753537 counting only the distinct ones).
The product of its (nonzero) digits is 105000, while the sum is 39.
The spelling of 5521105035147 in words is "five trillion, five hundred twenty-one billion, one hundred five million, thirty-five thousand, one hundred forty-seven".
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