Base | Representation |
---|---|
bin | 101000001010111101111… |
… | …1111001101100001101001 |
3 | 201112210221212102122120211 |
4 | 1100111323333031201221 |
5 | 1210424214431042101 |
6 | 15424210411421121 |
7 | 1106613221252452 |
oct | 120257377154151 |
9 | 21483855378524 |
10 | 5521113143401 |
11 | 18395444860a9 |
12 | 7520417547a1 |
13 | 31083c3bcbab |
14 | 15131aa52129 |
15 | 9893bba0c51 |
hex | 5057bfcd869 |
5521113143401 has 2 divisors, whose sum is σ = 5521113143402. Its totient is φ = 5521113143400.
The previous prime is 5521113143393. The next prime is 5521113143417. The reversal of 5521113143401 is 1043413111255.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4061740421376 + 1459372722025 = 2015376^2 + 1208045^2 .
It is a cyclic number.
It is not a de Polignac number, because 5521113143401 - 23 = 5521113143393 is a prime.
It is not a weakly prime, because it can be changed into another prime (5521113143501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2760556571700 + 2760556571701.
It is an arithmetic number, because the mean of its divisors is an integer number (2760556571701).
Almost surely, 25521113143401 is an apocalyptic number.
It is an amenable number.
5521113143401 is a deficient number, since it is larger than the sum of its proper divisors (1).
5521113143401 is an equidigital number, since it uses as much as digits as its factorization.
5521113143401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 5521113143401 its reverse (1043413111255), we get a palindrome (6564526254656).
The spelling of 5521113143401 in words is "five trillion, five hundred twenty-one billion, one hundred thirteen million, one hundred forty-three thousand, four hundred one".
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