Base | Representation |
---|---|
bin | 110011011010111110… |
… | …100110100111100011 |
3 | 12021111220211221221022 |
4 | 303122332212213203 |
5 | 1401034120423442 |
6 | 41210435520055 |
7 | 3663145411346 |
oct | 633276464743 |
9 | 167456757838 |
10 | 55213451747 |
11 | 21463610563 |
12 | a84aa5902b |
13 | 528bbb560c |
14 | 295acb645d |
15 | 16824113d2 |
hex | cdafa69e3 |
55213451747 has 2 divisors, whose sum is σ = 55213451748. Its totient is φ = 55213451746.
The previous prime is 55213451743. The next prime is 55213451791. The reversal of 55213451747 is 74715431255.
It is an a-pointer prime, because the next prime (55213451791) can be obtained adding 55213451747 to its sum of digits (44).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55213451747 - 22 = 55213451743 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 55213451698 and 55213451707.
It is not a weakly prime, because it can be changed into another prime (55213451743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27606725873 + 27606725874.
It is an arithmetic number, because the mean of its divisors is an integer number (27606725874).
Almost surely, 255213451747 is an apocalyptic number.
55213451747 is a deficient number, since it is larger than the sum of its proper divisors (1).
55213451747 is an equidigital number, since it uses as much as digits as its factorization.
55213451747 is an evil number, because the sum of its binary digits is even.
The product of its digits is 588000, while the sum is 44.
The spelling of 55213451747 in words is "fifty-five billion, two hundred thirteen million, four hundred fifty-one thousand, seven hundred forty-seven".
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