Base | Representation |
---|---|
bin | 110011011011000101… |
… | …000001000110110111 |
3 | 12021112001000101100001 |
4 | 303123011001012313 |
5 | 1401040033224421 |
6 | 41210535532131 |
7 | 3663165613315 |
oct | 633305010667 |
9 | 167461011301 |
10 | 55215133111 |
11 | 21464559816 |
12 | a84b52a047 |
13 | 528c3539c8 |
14 | 295b1d30b5 |
15 | 1682644691 |
hex | cdb1411b7 |
55215133111 has 2 divisors, whose sum is σ = 55215133112. Its totient is φ = 55215133110.
The previous prime is 55215133097. The next prime is 55215133117. The reversal of 55215133111 is 11133151255.
55215133111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55215133111 - 25 = 55215133079 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 55215133111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55215133117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27607566555 + 27607566556.
It is an arithmetic number, because the mean of its divisors is an integer number (27607566556).
Almost surely, 255215133111 is an apocalyptic number.
55215133111 is a deficient number, since it is larger than the sum of its proper divisors (1).
55215133111 is an equidigital number, since it uses as much as digits as its factorization.
55215133111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2250, while the sum is 28.
Adding to 55215133111 its reverse (11133151255), we get a palindrome (66348284366).
The spelling of 55215133111 in words is "fifty-five billion, two hundred fifteen million, one hundred thirty-three thousand, one hundred eleven".
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