Base | Representation |
---|---|
bin | 111110110001111011101110… |
… | …0010110011010100100100101 |
3 | 2200102020202201000001201000111 |
4 | 1331203313130112122210211 |
5 | 1034340040114403342013 |
6 | 5234250335151213021 |
7 | 224213421310644400 |
oct | 17543673426324445 |
9 | 2612222630051014 |
10 | 552220527012133 |
11 | 14aa55457158981 |
12 | 51b28055217171 |
13 | 1a919231596c05 |
14 | 9a5188a8a4d37 |
15 | 43c97cab2c73d |
hex | 1f63ddc59a925 |
552220527012133 has 12 divisors (see below), whose sum is σ = 644056210137600. Its totient is φ = 472096026806712.
The previous prime is 552220527012101. The next prime is 552220527012227. The reversal of 552220527012133 is 331210725022255.
It is not a de Polignac number, because 552220527012133 - 25 = 552220527012101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (552220527012433) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 14712522583 + ... + 14712560116.
It is an arithmetic number, because the mean of its divisors is an integer number (53671350844800).
Almost surely, 2552220527012133 is an apocalyptic number.
It is an amenable number.
552220527012133 is a deficient number, since it is larger than the sum of its proper divisors (91835683125467).
552220527012133 is a wasteful number, since it uses less digits than its factorization.
552220527012133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29425083096 (or 29425083089 counting only the distinct ones).
The product of its (nonzero) digits is 252000, while the sum is 40.
The spelling of 552220527012133 in words is "five hundred fifty-two trillion, two hundred twenty billion, five hundred twenty-seven million, twelve thousand, one hundred thirty-three".
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