Base | Representation |
---|---|
bin | 110011011011011111… |
… | …110011000011111111 |
3 | 12021112112020001110101 |
4 | 303123133303003333 |
5 | 1401043332402341 |
6 | 41211350221531 |
7 | 3663312362662 |
oct | 633337630377 |
9 | 167475201411 |
10 | 55222153471 |
11 | 21468514271 |
12 | a8519548a7 |
13 | 5290941274 |
14 | 295c0dd6d9 |
15 | 168307e831 |
hex | cdb7f30ff |
55222153471 has 2 divisors, whose sum is σ = 55222153472. Its totient is φ = 55222153470.
The previous prime is 55222153417. The next prime is 55222153517. The reversal of 55222153471 is 17435122255.
Together with previous prime (55222153417) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55222153471 - 223 = 55213764863 is a prime.
It is a super-3 number, since 3×552221534713 (a number of 33 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 55222153471.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55222153411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27611076735 + 27611076736.
It is an arithmetic number, because the mean of its divisors is an integer number (27611076736).
Almost surely, 255222153471 is an apocalyptic number.
55222153471 is a deficient number, since it is larger than the sum of its proper divisors (1).
55222153471 is an equidigital number, since it uses as much as digits as its factorization.
55222153471 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 84000, while the sum is 37.
The spelling of 55222153471 in words is "fifty-five billion, two hundred twenty-two million, one hundred fifty-three thousand, four hundred seventy-one".
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