Base | Representation |
---|---|
bin | 11001000111010001001111… |
… | …01011001011001011111011 |
3 | 21020112111021221200200211221 |
4 | 30203220213223023023323 |
5 | 24214303011402341103 |
6 | 313242102232132511 |
7 | 14426620532206105 |
oct | 1443504753131373 |
9 | 236474257620757 |
10 | 55225355121403 |
11 | 16661a3a275835 |
12 | 623b063837137 |
13 | 24a7961a99c0c |
14 | d8ccc865a575 |
15 | 65b8117741bd |
hex | 323a27acb2fb |
55225355121403 has 4 divisors (see below), whose sum is σ = 58473905422680. Its totient is φ = 51976804820128.
The previous prime is 55225355121379. The next prime is 55225355121473. The reversal of 55225355121403 is 30412155352255.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55225355121403 - 29 = 55225355120891 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 55225355121403.
It is not an unprimeable number, because it can be changed into a prime (55225355121473) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1624275150613 + ... + 1624275150646.
It is an arithmetic number, because the mean of its divisors is an integer number (14618476355670).
Almost surely, 255225355121403 is an apocalyptic number.
55225355121403 is a deficient number, since it is larger than the sum of its proper divisors (3248550301277).
55225355121403 is a wasteful number, since it uses less digits than its factorization.
55225355121403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3248550301276.
The product of its (nonzero) digits is 900000, while the sum is 43.
The spelling of 55225355121403 in words is "fifty-five trillion, two hundred twenty-five billion, three hundred fifty-five million, one hundred twenty-one thousand, four hundred three".
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