Base | Representation |
---|---|
bin | 11001000111011100100000… |
… | …01110011001101011000101 |
3 | 21020120001220112000100222021 |
4 | 30203232100032121223011 |
5 | 24214402403430403131 |
6 | 313244542400003141 |
7 | 14430223453141240 |
oct | 1443562016315305 |
9 | 236501815010867 |
10 | 55231404153541 |
11 | 16664563846150 |
12 | 62402716004b1 |
13 | 24a83b7072685 |
14 | d8d2ddb90257 |
15 | 65ba67844e11 |
hex | 323b90399ac5 |
55231404153541 has 16 divisors (see below), whose sum is σ = 69491674961280. Its totient is φ = 42642618713280.
The previous prime is 55231404153529. The next prime is 55231404153547. The reversal of 55231404153541 is 14535140413255.
It is a cyclic number.
It is not a de Polignac number, because 55231404153541 - 231 = 55229256669893 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55231404153547) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3290317126 + ... + 3290333911.
It is an arithmetic number, because the mean of its divisors is an integer number (4343229685080).
Almost surely, 255231404153541 is an apocalyptic number.
It is an amenable number.
55231404153541 is a deficient number, since it is larger than the sum of its proper divisors (14260270807739).
55231404153541 is a wasteful number, since it uses less digits than its factorization.
55231404153541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6580651164.
The product of its (nonzero) digits is 720000, while the sum is 43.
Adding to 55231404153541 its reverse (14535140413255), we get a palindrome (69766544566796).
The spelling of 55231404153541 in words is "fifty-five trillion, two hundred thirty-one billion, four hundred four million, one hundred fifty-three thousand, five hundred forty-one".
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