Base | Representation |
---|---|
bin | 11001000111011100110100… |
… | …10100110101100111001001 |
3 | 21020120002100022212210122120 |
4 | 30203232122110311213021 |
5 | 24214403230321104001 |
6 | 313245011252041453 |
7 | 14430230611416162 |
oct | 1443563224654711 |
9 | 236502308783576 |
10 | 55231573613001 |
11 | 16664640469595 |
12 | 62402ba303289 |
13 | 24a84131c5946 |
14 | d8d3184a2769 |
15 | 65ba7766a236 |
hex | 323b9a5359c9 |
55231573613001 has 8 divisors (see below), whose sum is σ = 73692850808544. Its totient is φ = 36795672746400.
The previous prime is 55231573612993. The next prime is 55231573613003. The reversal of 55231573613001 is 10031637513255.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 55231573613001 - 23 = 55231573612993 is a prime.
It is not an unprimeable number, because it can be changed into a prime (55231573613003) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6344077156 + ... + 6344085861.
It is an arithmetic number, because the mean of its divisors is an integer number (9211606351068).
Almost surely, 255231573613001 is an apocalyptic number.
It is an amenable number.
55231573613001 is a deficient number, since it is larger than the sum of its proper divisors (18461277195543).
55231573613001 is a wasteful number, since it uses less digits than its factorization.
55231573613001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12688164471.
The product of its (nonzero) digits is 283500, while the sum is 42.
The spelling of 55231573613001 in words is "fifty-five trillion, two hundred thirty-one billion, five hundred seventy-three million, six hundred thirteen thousand, one".
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