Base | Representation |
---|---|
bin | 11001000111101111000010… |
… | …00100110111101011110011 |
3 | 21020121000120200220100210100 |
4 | 30203313201010313223303 |
5 | 24220033241214402430 |
6 | 313253305345403443 |
7 | 14431025110103421 |
oct | 1443674104675363 |
9 | 236530520810710 |
10 | 55241350544115 |
11 | 166687a827464a |
12 | 6242188639583 |
13 | 24a931090c898 |
14 | d8d9a4b5a111 |
15 | 65be4ab63960 |
hex | 323de1137af3 |
55241350544115 has 24 divisors (see below), whose sum is σ = 95752139603328. Its totient is φ = 29461910446080.
The previous prime is 55241350544077. The next prime is 55241350544131. The reversal of 55241350544115 is 51144505314255.
55241350544115 is a `hidden beast` number, since 5 + 5 + 2 + 41 + 3 + 50 + 544 + 1 + 15 = 666.
It is not a de Polignac number, because 55241350544115 - 213 = 55241350535923 is a prime.
It is a super-2 number, since 2×552413505441152 (a number of 28 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (45).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6727155 + ... + 12479475.
It is an arithmetic number, because the mean of its divisors is an integer number (3989672483472).
Almost surely, 255241350544115 is an apocalyptic number.
55241350544115 is a deficient number, since it is larger than the sum of its proper divisors (40510789059213).
55241350544115 is a wasteful number, since it uses less digits than its factorization.
55241350544115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5965739 (or 5965736 counting only the distinct ones).
The product of its (nonzero) digits is 1200000, while the sum is 45.
The spelling of 55241350544115 in words is "fifty-five trillion, two hundred forty-one billion, three hundred fifty million, five hundred forty-four thousand, one hundred fifteen".
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