Base | Representation |
---|---|
bin | 111110110011011101011000… |
… | …0001110011001101001111111 |
3 | 2200102222211000021020221120221 |
4 | 1331212322300032121221333 |
5 | 1034402004112432024411 |
6 | 5234530540534522211 |
7 | 224234524223611516 |
oct | 17546726016315177 |
9 | 2612884007227527 |
10 | 552430240111231 |
11 | 1500263927971a9 |
12 | 51b60821806367 |
13 | 1a932c43010ab1 |
14 | 9a5baa298567d |
15 | 43ceea1b8c071 |
hex | 1f66eb0399a7f |
552430240111231 has 2 divisors, whose sum is σ = 552430240111232. Its totient is φ = 552430240111230.
The previous prime is 552430240111223. The next prime is 552430240111237. The reversal of 552430240111231 is 132111042034255.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 552430240111231 - 23 = 552430240111223 is a prime.
It is a super-2 number, since 2×5524302401112312 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (552430240111237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276215120055615 + 276215120055616.
It is an arithmetic number, because the mean of its divisors is an integer number (276215120055616).
Almost surely, 2552430240111231 is an apocalyptic number.
552430240111231 is a deficient number, since it is larger than the sum of its proper divisors (1).
552430240111231 is an equidigital number, since it uses as much as digits as its factorization.
552430240111231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 552430240111231 its reverse (132111042034255), we get a palindrome (684541282145486).
The spelling of 552430240111231 in words is "five hundred fifty-two trillion, four hundred thirty billion, two hundred forty million, one hundred eleven thousand, two hundred thirty-one".
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