Base | Representation |
---|---|
bin | 10000000101000001101… |
… | …00110001001010011111 |
3 | 1221210222110200001210211 |
4 | 20002200310301022133 |
5 | 33022411211020221 |
6 | 1101443250313251 |
7 | 54625216350022 |
oct | 10024064611237 |
9 | 1853873601724 |
10 | 552454001311 |
11 | 1a3326977003 |
12 | 8b09b888827 |
13 | 40133432b84 |
14 | 1ca4b82d1b9 |
15 | e585b696e1 |
hex | 80a0d3129f |
552454001311 has 2 divisors, whose sum is σ = 552454001312. Its totient is φ = 552454001310.
The previous prime is 552454001287. The next prime is 552454001321. The reversal of 552454001311 is 113100454255.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 552454001311 - 221 = 552451904159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (552454001321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276227000655 + 276227000656.
It is an arithmetic number, because the mean of its divisors is an integer number (276227000656).
Almost surely, 2552454001311 is an apocalyptic number.
552454001311 is a deficient number, since it is larger than the sum of its proper divisors (1).
552454001311 is an equidigital number, since it uses as much as digits as its factorization.
552454001311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 552454001311 its reverse (113100454255), we get a palindrome (665554455566).
The spelling of 552454001311 in words is "five hundred fifty-two billion, four hundred fifty-four million, one thousand, three hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •