Base | Representation |
---|---|
bin | 11001001000000100110101… |
… | …01111101111000000001111 |
3 | 21020122010210102211202010012 |
4 | 30210002122233233000033 |
5 | 24220231224202002203 |
6 | 313302523035303435 |
7 | 14431621136432213 |
oct | 1444023257570017 |
9 | 236563712752105 |
10 | 55253055500303 |
11 | 16672764427461 |
12 | 62444b45aab7b |
13 | 24aa4578c046b |
14 | d903954d4943 |
15 | 65c3d3553bd8 |
hex | 32409abef00f |
55253055500303 has 4 divisors (see below), whose sum is σ = 55359107430768. Its totient is φ = 55147003569840.
The previous prime is 55253055500281. The next prime is 55253055500329. The reversal of 55253055500303 is 30300555035255.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55253055500303 - 28 = 55253055500047 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55253055500393) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53025964451 + ... + 53025965492.
It is an arithmetic number, because the mean of its divisors is an integer number (13839776857692).
Almost surely, 255253055500303 is an apocalyptic number.
55253055500303 is a deficient number, since it is larger than the sum of its proper divisors (106051930465).
55253055500303 is a wasteful number, since it uses less digits than its factorization.
55253055500303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106051930464.
The product of its (nonzero) digits is 843750, while the sum is 41.
The spelling of 55253055500303 in words is "fifty-five trillion, two hundred fifty-three billion, fifty-five million, five hundred thousand, three hundred three".
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